Integrand size = 30, antiderivative size = 280 \[ \int \frac {\sqrt {d+e x}}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=-\frac {5 e^3 \sqrt {d+e x}}{64 b (b d-a e)^3 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {\sqrt {d+e x}}{4 b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {e \sqrt {d+e x}}{24 b (b d-a e) (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {5 e^2 \sqrt {d+e x}}{96 b (b d-a e)^2 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {5 e^4 (a+b x) \text {arctanh}\left (\frac {\sqrt {b} \sqrt {d+e x}}{\sqrt {b d-a e}}\right )}{64 b^{3/2} (b d-a e)^{7/2} \sqrt {a^2+2 a b x+b^2 x^2}} \]
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Time = 0.12 (sec) , antiderivative size = 280, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {660, 43, 44, 65, 214} \[ \int \frac {\sqrt {d+e x}}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=\frac {5 e^4 (a+b x) \text {arctanh}\left (\frac {\sqrt {b} \sqrt {d+e x}}{\sqrt {b d-a e}}\right )}{64 b^{3/2} \sqrt {a^2+2 a b x+b^2 x^2} (b d-a e)^{7/2}}-\frac {5 e^3 \sqrt {d+e x}}{64 b \sqrt {a^2+2 a b x+b^2 x^2} (b d-a e)^3}+\frac {5 e^2 \sqrt {d+e x}}{96 b (a+b x) \sqrt {a^2+2 a b x+b^2 x^2} (b d-a e)^2}-\frac {e \sqrt {d+e x}}{24 b (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2} (b d-a e)}-\frac {\sqrt {d+e x}}{4 b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}} \]
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Rule 43
Rule 44
Rule 65
Rule 214
Rule 660
Rubi steps \begin{align*} \text {integral}& = \frac {\left (b^4 \left (a b+b^2 x\right )\right ) \int \frac {\sqrt {d+e x}}{\left (a b+b^2 x\right )^5} \, dx}{\sqrt {a^2+2 a b x+b^2 x^2}} \\ & = -\frac {\sqrt {d+e x}}{4 b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {\left (b^2 e \left (a b+b^2 x\right )\right ) \int \frac {1}{\left (a b+b^2 x\right )^4 \sqrt {d+e x}} \, dx}{8 \sqrt {a^2+2 a b x+b^2 x^2}} \\ & = -\frac {\sqrt {d+e x}}{4 b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {e \sqrt {d+e x}}{24 b (b d-a e) (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {\left (5 b e^2 \left (a b+b^2 x\right )\right ) \int \frac {1}{\left (a b+b^2 x\right )^3 \sqrt {d+e x}} \, dx}{48 (b d-a e) \sqrt {a^2+2 a b x+b^2 x^2}} \\ & = -\frac {\sqrt {d+e x}}{4 b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {e \sqrt {d+e x}}{24 b (b d-a e) (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {5 e^2 \sqrt {d+e x}}{96 b (b d-a e)^2 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {\left (5 e^3 \left (a b+b^2 x\right )\right ) \int \frac {1}{\left (a b+b^2 x\right )^2 \sqrt {d+e x}} \, dx}{64 (b d-a e)^2 \sqrt {a^2+2 a b x+b^2 x^2}} \\ & = -\frac {5 e^3 \sqrt {d+e x}}{64 b (b d-a e)^3 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {\sqrt {d+e x}}{4 b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {e \sqrt {d+e x}}{24 b (b d-a e) (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {5 e^2 \sqrt {d+e x}}{96 b (b d-a e)^2 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {\left (5 e^4 \left (a b+b^2 x\right )\right ) \int \frac {1}{\left (a b+b^2 x\right ) \sqrt {d+e x}} \, dx}{128 b (b d-a e)^3 \sqrt {a^2+2 a b x+b^2 x^2}} \\ & = -\frac {5 e^3 \sqrt {d+e x}}{64 b (b d-a e)^3 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {\sqrt {d+e x}}{4 b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {e \sqrt {d+e x}}{24 b (b d-a e) (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {5 e^2 \sqrt {d+e x}}{96 b (b d-a e)^2 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {\left (5 e^3 \left (a b+b^2 x\right )\right ) \text {Subst}\left (\int \frac {1}{a b-\frac {b^2 d}{e}+\frac {b^2 x^2}{e}} \, dx,x,\sqrt {d+e x}\right )}{64 b (b d-a e)^3 \sqrt {a^2+2 a b x+b^2 x^2}} \\ & = -\frac {5 e^3 \sqrt {d+e x}}{64 b (b d-a e)^3 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {\sqrt {d+e x}}{4 b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {e \sqrt {d+e x}}{24 b (b d-a e) (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {5 e^2 \sqrt {d+e x}}{96 b (b d-a e)^2 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {5 e^4 (a+b x) \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {d+e x}}{\sqrt {b d-a e}}\right )}{64 b^{3/2} (b d-a e)^{7/2} \sqrt {a^2+2 a b x+b^2 x^2}} \\ \end{align*}
Time = 0.85 (sec) , antiderivative size = 192, normalized size of antiderivative = 0.69 \[ \int \frac {\sqrt {d+e x}}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=\frac {e^4 (a+b x)^5 \left (\frac {\sqrt {b} \sqrt {d+e x} \left (-15 a^3 e^3+a^2 b e^2 (118 d+73 e x)+a b^2 e \left (-136 d^2-36 d e x+55 e^2 x^2\right )+b^3 \left (48 d^3+8 d^2 e x-10 d e^2 x^2+15 e^3 x^3\right )\right )}{e^4 (-b d+a e)^3 (a+b x)^4}+\frac {15 \arctan \left (\frac {\sqrt {b} \sqrt {d+e x}}{\sqrt {-b d+a e}}\right )}{(-b d+a e)^{7/2}}\right )}{192 b^{3/2} \left ((a+b x)^2\right )^{5/2}} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(499\) vs. \(2(197)=394\).
Time = 2.29 (sec) , antiderivative size = 500, normalized size of antiderivative = 1.79
method | result | size |
default | \(\frac {\left (b x +a \right ) \left (15 \arctan \left (\frac {b \sqrt {e x +d}}{\sqrt {\left (a e -b d \right ) b}}\right ) b^{4} e^{4} x^{4}+60 \arctan \left (\frac {b \sqrt {e x +d}}{\sqrt {\left (a e -b d \right ) b}}\right ) a \,b^{3} e^{4} x^{3}+15 \sqrt {\left (a e -b d \right ) b}\, \left (e x +d \right )^{\frac {7}{2}} b^{3}+90 \arctan \left (\frac {b \sqrt {e x +d}}{\sqrt {\left (a e -b d \right ) b}}\right ) a^{2} b^{2} e^{4} x^{2}+55 \left (e x +d \right )^{\frac {5}{2}} \sqrt {\left (a e -b d \right ) b}\, a \,b^{2} e -55 \left (e x +d \right )^{\frac {5}{2}} \sqrt {\left (a e -b d \right ) b}\, b^{3} d +60 \arctan \left (\frac {b \sqrt {e x +d}}{\sqrt {\left (a e -b d \right ) b}}\right ) a^{3} b \,e^{4} x +73 \sqrt {\left (a e -b d \right ) b}\, \left (e x +d \right )^{\frac {3}{2}} a^{2} b \,e^{2}-146 \sqrt {\left (a e -b d \right ) b}\, \left (e x +d \right )^{\frac {3}{2}} a \,b^{2} d e +73 \sqrt {\left (a e -b d \right ) b}\, \left (e x +d \right )^{\frac {3}{2}} b^{3} d^{2}+15 \arctan \left (\frac {b \sqrt {e x +d}}{\sqrt {\left (a e -b d \right ) b}}\right ) a^{4} e^{4}-15 \sqrt {e x +d}\, a^{3} e^{3} \sqrt {\left (a e -b d \right ) b}+45 \sqrt {e x +d}\, a^{2} d \,e^{2} b \sqrt {\left (a e -b d \right ) b}-45 \sqrt {e x +d}\, a \,d^{2} e \,b^{2} \sqrt {\left (a e -b d \right ) b}+15 \sqrt {e x +d}\, d^{3} b^{3} \sqrt {\left (a e -b d \right ) b}\right )}{192 \sqrt {\left (a e -b d \right ) b}\, b \left (a e -b d \right ) \left (a^{2} e^{2}-2 a b d e +b^{2} d^{2}\right ) \left (\left (b x +a \right )^{2}\right )^{\frac {5}{2}}}\) | \(500\) |
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Leaf count of result is larger than twice the leaf count of optimal. 581 vs. \(2 (197) = 394\).
Time = 0.34 (sec) , antiderivative size = 1176, normalized size of antiderivative = 4.20 \[ \int \frac {\sqrt {d+e x}}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=\left [-\frac {15 \, {\left (b^{4} e^{4} x^{4} + 4 \, a b^{3} e^{4} x^{3} + 6 \, a^{2} b^{2} e^{4} x^{2} + 4 \, a^{3} b e^{4} x + a^{4} e^{4}\right )} \sqrt {b^{2} d - a b e} \log \left (\frac {b e x + 2 \, b d - a e - 2 \, \sqrt {b^{2} d - a b e} \sqrt {e x + d}}{b x + a}\right ) + 2 \, {\left (48 \, b^{5} d^{4} - 184 \, a b^{4} d^{3} e + 254 \, a^{2} b^{3} d^{2} e^{2} - 133 \, a^{3} b^{2} d e^{3} + 15 \, a^{4} b e^{4} + 15 \, {\left (b^{5} d e^{3} - a b^{4} e^{4}\right )} x^{3} - 5 \, {\left (2 \, b^{5} d^{2} e^{2} - 13 \, a b^{4} d e^{3} + 11 \, a^{2} b^{3} e^{4}\right )} x^{2} + {\left (8 \, b^{5} d^{3} e - 44 \, a b^{4} d^{2} e^{2} + 109 \, a^{2} b^{3} d e^{3} - 73 \, a^{3} b^{2} e^{4}\right )} x\right )} \sqrt {e x + d}}{384 \, {\left (a^{4} b^{6} d^{4} - 4 \, a^{5} b^{5} d^{3} e + 6 \, a^{6} b^{4} d^{2} e^{2} - 4 \, a^{7} b^{3} d e^{3} + a^{8} b^{2} e^{4} + {\left (b^{10} d^{4} - 4 \, a b^{9} d^{3} e + 6 \, a^{2} b^{8} d^{2} e^{2} - 4 \, a^{3} b^{7} d e^{3} + a^{4} b^{6} e^{4}\right )} x^{4} + 4 \, {\left (a b^{9} d^{4} - 4 \, a^{2} b^{8} d^{3} e + 6 \, a^{3} b^{7} d^{2} e^{2} - 4 \, a^{4} b^{6} d e^{3} + a^{5} b^{5} e^{4}\right )} x^{3} + 6 \, {\left (a^{2} b^{8} d^{4} - 4 \, a^{3} b^{7} d^{3} e + 6 \, a^{4} b^{6} d^{2} e^{2} - 4 \, a^{5} b^{5} d e^{3} + a^{6} b^{4} e^{4}\right )} x^{2} + 4 \, {\left (a^{3} b^{7} d^{4} - 4 \, a^{4} b^{6} d^{3} e + 6 \, a^{5} b^{5} d^{2} e^{2} - 4 \, a^{6} b^{4} d e^{3} + a^{7} b^{3} e^{4}\right )} x\right )}}, -\frac {15 \, {\left (b^{4} e^{4} x^{4} + 4 \, a b^{3} e^{4} x^{3} + 6 \, a^{2} b^{2} e^{4} x^{2} + 4 \, a^{3} b e^{4} x + a^{4} e^{4}\right )} \sqrt {-b^{2} d + a b e} \arctan \left (\frac {\sqrt {-b^{2} d + a b e} \sqrt {e x + d}}{b e x + b d}\right ) + {\left (48 \, b^{5} d^{4} - 184 \, a b^{4} d^{3} e + 254 \, a^{2} b^{3} d^{2} e^{2} - 133 \, a^{3} b^{2} d e^{3} + 15 \, a^{4} b e^{4} + 15 \, {\left (b^{5} d e^{3} - a b^{4} e^{4}\right )} x^{3} - 5 \, {\left (2 \, b^{5} d^{2} e^{2} - 13 \, a b^{4} d e^{3} + 11 \, a^{2} b^{3} e^{4}\right )} x^{2} + {\left (8 \, b^{5} d^{3} e - 44 \, a b^{4} d^{2} e^{2} + 109 \, a^{2} b^{3} d e^{3} - 73 \, a^{3} b^{2} e^{4}\right )} x\right )} \sqrt {e x + d}}{192 \, {\left (a^{4} b^{6} d^{4} - 4 \, a^{5} b^{5} d^{3} e + 6 \, a^{6} b^{4} d^{2} e^{2} - 4 \, a^{7} b^{3} d e^{3} + a^{8} b^{2} e^{4} + {\left (b^{10} d^{4} - 4 \, a b^{9} d^{3} e + 6 \, a^{2} b^{8} d^{2} e^{2} - 4 \, a^{3} b^{7} d e^{3} + a^{4} b^{6} e^{4}\right )} x^{4} + 4 \, {\left (a b^{9} d^{4} - 4 \, a^{2} b^{8} d^{3} e + 6 \, a^{3} b^{7} d^{2} e^{2} - 4 \, a^{4} b^{6} d e^{3} + a^{5} b^{5} e^{4}\right )} x^{3} + 6 \, {\left (a^{2} b^{8} d^{4} - 4 \, a^{3} b^{7} d^{3} e + 6 \, a^{4} b^{6} d^{2} e^{2} - 4 \, a^{5} b^{5} d e^{3} + a^{6} b^{4} e^{4}\right )} x^{2} + 4 \, {\left (a^{3} b^{7} d^{4} - 4 \, a^{4} b^{6} d^{3} e + 6 \, a^{5} b^{5} d^{2} e^{2} - 4 \, a^{6} b^{4} d e^{3} + a^{7} b^{3} e^{4}\right )} x\right )}}\right ] \]
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\[ \int \frac {\sqrt {d+e x}}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=\int \frac {\sqrt {d + e x}}{\left (\left (a + b x\right )^{2}\right )^{\frac {5}{2}}}\, dx \]
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\[ \int \frac {\sqrt {d+e x}}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=\int { \frac {\sqrt {e x + d}}{{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {5}{2}}} \,d x } \]
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Time = 0.32 (sec) , antiderivative size = 359, normalized size of antiderivative = 1.28 \[ \int \frac {\sqrt {d+e x}}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=-\frac {5 \, e^{4} \arctan \left (\frac {\sqrt {e x + d} b}{\sqrt {-b^{2} d + a b e}}\right )}{64 \, {\left (b^{4} d^{3} \mathrm {sgn}\left (b x + a\right ) - 3 \, a b^{3} d^{2} e \mathrm {sgn}\left (b x + a\right ) + 3 \, a^{2} b^{2} d e^{2} \mathrm {sgn}\left (b x + a\right ) - a^{3} b e^{3} \mathrm {sgn}\left (b x + a\right )\right )} \sqrt {-b^{2} d + a b e}} - \frac {15 \, {\left (e x + d\right )}^{\frac {7}{2}} b^{3} e^{4} - 55 \, {\left (e x + d\right )}^{\frac {5}{2}} b^{3} d e^{4} + 73 \, {\left (e x + d\right )}^{\frac {3}{2}} b^{3} d^{2} e^{4} + 15 \, \sqrt {e x + d} b^{3} d^{3} e^{4} + 55 \, {\left (e x + d\right )}^{\frac {5}{2}} a b^{2} e^{5} - 146 \, {\left (e x + d\right )}^{\frac {3}{2}} a b^{2} d e^{5} - 45 \, \sqrt {e x + d} a b^{2} d^{2} e^{5} + 73 \, {\left (e x + d\right )}^{\frac {3}{2}} a^{2} b e^{6} + 45 \, \sqrt {e x + d} a^{2} b d e^{6} - 15 \, \sqrt {e x + d} a^{3} e^{7}}{192 \, {\left (b^{4} d^{3} \mathrm {sgn}\left (b x + a\right ) - 3 \, a b^{3} d^{2} e \mathrm {sgn}\left (b x + a\right ) + 3 \, a^{2} b^{2} d e^{2} \mathrm {sgn}\left (b x + a\right ) - a^{3} b e^{3} \mathrm {sgn}\left (b x + a\right )\right )} {\left ({\left (e x + d\right )} b - b d + a e\right )}^{4}} \]
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Timed out. \[ \int \frac {\sqrt {d+e x}}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=\int \frac {\sqrt {d+e\,x}}{{\left (a^2+2\,a\,b\,x+b^2\,x^2\right )}^{5/2}} \,d x \]
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